Crown PIP-BP1X Información técnica Pagina 29

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Page 29Reference Manual
Macro-Tech
®
24x6 & 36x12 Power Amplifiers
Fig. 7.2 Macro-Tech 36x12 Power Draw, Current Draw and
Thermal Dissipation at Various Duty Cycles
7 AC Power Draw and
Thermal Dissipation
This section provides detailed information about the
amount of power and current drawn from the AC mains
by the Macro-Tech 24x6 and 36x12 amplifiers and the
amount of heat produced under various conditions. The
calculations presented here are intended to provide a
realistic and reliable depiction of the amplifiers. The fol-
lowing assumptions or approximations were made:
The amplifiers available channels are loaded and full
power is being delivered.
The amplifier efficiency at standard 1 kHz power is
estimated to be 65%.
Quiescent power draw is 90 watts (an almost negli-
gible amount for full-power calculations).
Quiescent thermal dissipation equals 105 btu/hr at
90 watts.
The estimated duty cycles take into account the typi-
cal crest factor for each type of source material.
Duty cycle of pink noise is 50%.
Duty cycle of highly compressed rock n roll mid-
range is 40%.
Duty cycle of rock n roll is 30%.
Duty cycle of background music is 20%.
Duty cycle of continuous speech is 10%.
Duty cycle of infrequent, short duration paging is 1%.
Here are the equations used to calculate the data pre-
sented in Figures 7.1 and 7.2:
AC Mains Power
Draw (watts)
=
Total output power will all
channels driven (watts)
x
Duty
Cycle
Amplifier Efficiency (.65)
+
Quiescent Power
Draw (watts)
The quiescent power draw of 90 watts is a maximum
value and includes power drawn by the fan. The follow-
ing equation converts power draw in watts to current
draw in amperes:
Current Draw
(amperes)
=
AC Mains Power
Draw (watts)
x
AC Mains
Volta
g
e
Power
Factor
(
.83
)
The power factor of 0.83 is needed to compensate for
the difference in phase between the AC mains voltage
and current. The following equation is used to calculate
thermal dissipation:
Total output power with all
channels driven (watts)
Thermal
Dissipation
(btu/hr)
=
+
Quiescent Power
Draw (watts)
x
Duty
Cycle
Amplifier Efficiency (.65)
()
x
3.415
.35
x
The constant 0.35 is inefficiency (1.000.65) and the
factor 3.415 converts watts to btu/hr. Thermal dissipa-
tion in btu is divided by the constant 3.968 to get kcal. If
you plan to measure output power under real-world con-
ditions, the following equation may also be helpful:
Total measured output power
from all channels (watts)
Thermal
Dissipation
(btu/hr)
=
+
Quiescent Power
Draw (watts)
.35
x
Amplifier Efficiency (.65)
()
x
3.415
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